00:01
Today we're looking at using figure 8 .3 in order to determine electronegativities and bond polarities from 28 and 30.
00:10
So first on the left we have just determining which one are ordering these in increasing order of increasing electronegativity.
00:21
So we're going to look and see which one of these has the largest number that would be the highest electronegativity and which one has the lowest number on that chart, which would be the lowest electron negativity.
00:31
Negativity.
00:32
So sodium is 0 .9, potassium is 0 .8, and rubidium is 0 .8.
00:41
So these would be ordered k, rb, and then n, for increasing electronegativity.
00:50
Next, we have boron, which is 2 .0, oxygen, which is 3 .5, and gallium, which is 1 .6.
01:01
So this would be gallium, boron, oxygen.
01:06
Next, we have fluorine, chlorine, and bromine.
01:10
This is 4, 3, and 2 .8.
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So we would just order these opposite.
01:20
And then lastly, we have sulfur, oxygen, and fluorine.
01:24
So if there is 2 .5, oxygen is 3 .5, and fluorine is 4.
01:29
So these are already ordered correctly.
01:32
Now to find bond polarities, we look at the electron negativity of each atom in the bond, and subtract their electron -negativities to find out bond polarity.
01:42
Now, the bigger the number is after subtraction, then the bigger the bond polarity is.
01:48
So a larger difference between the electronegativity of the two atoms gives us a larger bond polarity.
01:55
So here we're comparing different things bound to hydrogen.
01:59
Hydrogen's electronegativity is 2 .1.
02:06
So we're comparing carbon, silicon, and tin.
02:09
So carbon is 2 .5, silicon is 1 .8, and 10 is 1 .8...