Repeat Problem 12.46, but solve using values from Table A.8....

Name: Problem 47, Chapter 12: Fundamentals of Thermodynamics
Uploaded: 2020-08-27T16:05:50-08:00
Duration: 6 min 24 s
Channel: Sarah Mccrumb
Description: Repeat Problem 12.46, but solve using values from Table A.8.

Key Concepts

Property Tables

Property Tables are compilations of experimentally determined or empirically calculated data for various materials. They are used to provide accurate physical property values such as density, viscosity, thermal conductivity, and specific heat, which are essential for solving engineering problems. Reading and understanding these tables is vital for ensuring that calculations use realistic, validated data rather than mere assumptions.

Data Substitution

Data Substitution involves replacing theoretical, assumed, or previously used values with updated or alternative values from a reliable source. In this context, it means re-solving a problem with new data obtained from a specific table, thus demonstrating how the solution can vary based on the input properties and ensuring that the method remains robust under different conditions.

Interpolation

Interpolation is the process of estimating values between two known data points in a table when the exact required value is not explicitly available. This mathematical technique ensures that the inserted values accurately reflect the expected behavior of the properties between the tabulated entries, thereby maintaining the precision of the engineering calculations.

Unit Consistency and Conversion

Unit Consistency and Conversion refer to the crucial practice of ensuring that all numerical values used in calculations are expressed in a common, consistent set of units. When using properties from a table, it is essential to verify that the units of the tabulated values match the units used in the problem’s equations. If necessary, appropriate unit conversions should be carried out to obtain correct and meaningful results.

Transcript

0:00 Hi, everybody.

00:01 So we need to repeat problems 12 .46 on the q4 this, but solve using values from table 8.

00:10 Okay? and so from this, we have a q equals work times the potential, and your work is going to be key, the volume, which equals m, pressure, times volume two minus volume.

00:31 1.

00:32 Okay.

00:34 And so your q is going to equal m of pressure terms volume 2 minus volume 1 plus m of v2 minus 1.

00:47 And this is going to equal to m h2 minus 81.

00:53 Okay.

00:54 And your qm is going to equal to h2 minus 81.

00:54 Okay.

00:54 And your qm is going to equal to h2 minus h1.

01:00 And so that means your h2 minus h1 is going to equal to 800 over 1 kilo for kilogram.

01:12 Okay.

01:13 And so we're going to look at the left hand side and just assume, and i'm going to write, assume that your t2 equals 1 ,000 kelvin's.

01:28 Okay.