00:01
Here we're going to be using gauss's law to look at some nested spheres.
00:07
So a reminder that gauss's law says that the electric field projected through a closed area, closed surface, that that is proportional to the amount of charge enclosed by that surface.
00:33
You almost never have to do the integral on the left -hand side.
00:39
In fact, if you have a sphere, spherical symmetry guarantees that the radial field of the electric component is the only one that exists and that it is constant on a spherical surface of radius 4 pi r squared, where r is an arbitrary radius that you get to draw for your gaussian surface.
01:06
And i will show an example of a gaussian surface around this situation.
01:14
So that is an example of an r out to a gaussian surface.
01:29
But as long as everything is symmetrical, that electric field is radial and uniform on that surface.
01:38
So in this example, what we can see is, so there are two metal spheres nested one inside the other.
01:50
The inner sphere extends from a to b, outer sphere from c to t, and two q is on the inner sphere minus 2q on the outer.
02:02
What we can tell immediately is because there are conductors, we should have no electric field inside either one.
02:20
Okay, so that is going to wipe out the electric field in the following regions, are less than or equal to b or greater than equal to a, and also the same for the outer shell.
02:46
In addition, because of gauss's law, inside the inner sphere and totally outside, there is no enclosed charge.
02:57
So no enclosed charge means that the electric field for r less than or equal to a and r greater than or equal to d, that the electric field is zero there.
03:16
So there is only one place that we are going to have an electric field, and it is due to, i can draw the surface inside that gap between the two spheres.
03:34
And so in the region, in that gap, so that is r greater than or equal to b, less than or equal to c, q enclosed is plus 2q...