00:01
Okay, so the terminal voltage can be equal to emf plus ir.
00:05
We know emf is 12 volts, we have 12 volt here.
00:08
And i, which is current here, is given as 30 ampere.
00:12
So it's 30 ampere, motivated by the internal resistance, which is 0 .24 omega.
00:18
And this is equal to 19 .2 volts.
00:25
So for the next question, it was asking us the total electrical energy dissipated to the back.
00:33
During the charging process.
00:35
We know this is equal to vit.
00:38
So the terminal voltage is 19 .2 volts.
00:41
The current is given as 30 ampere and it times 1 .7 hours now, which is 6 .12nd.
00:46
If we plug in back to the equation, we'll have a 19 .2 volts, multiply by 30 ampere, and then times 612nd.
00:58
And this is equal to 3 .53 times 10 to the power of a 6 .53 times 10 to the power of a 6.
01:06
So for the next question, it was asking us the electrical energy dissipated in the internal resistance, which is equal to isquare rt here.
01:18
So now it's plugging the values back into the equation to determine total energy dissipated in the internal resistance, which is equal to 30 ampere to the power 2, multiplied by 0 .24 omega times 61, 20 seconds...