Question
Repeat Problem 3.84 when each of the 3 players selects from his own urn. That is, suppose that there are 3 different urns of 12 balls with 4 white balls in each urn.
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We have 3 players, each selecting a ball from their own urn. Each urn contains 12 balls, with 4 white balls and 8 non-white balls. Show more…
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Repeat Problem 3.87 when each of the 3 players selects from their own urn. That is, suppose that there are 3 different urns of 12 balls with 4 white balls in each urn. An urn contains 12 balls, of which 4 are white. Three players—A, B, and successively C draw from the urn, A first, then B, then C, then A, and so on. The winner is the first one to draw a white ball. Find the probability of winning for each player if a. Each ball is replaced after it is drawn; b. The balls that are withdrawn are not replaced. Problem 3.87 An urn contains 12 balls, of which 4 are white. Three players A, B, and C successively draw from the urn, A first, then B, then C, then A, and so on. The winner is the first one to draw a white ball. Find the probability of winning for each player if a. Each ball is replaced after it is drawn; b. The balls that are withdrawn are not replaced;
An urn contains 12 balls, of which 4 are white. Three players $-A, B,$ and $C-$ successively draw from the urn, $A$ first, then $B$, then $C$, then $A$, and so on. The winner is the first one to draw a white ball. Find the probability of winning for each player if (a) each ball is replaced after it is drawn; (b) the balls that are withdrawn are not replaced.
Consider an urn containing 12 balls, of which 8 are white. A sample of size 4 is to be drawn with replacement (without replacement). What is the conditional probability (in each case) that the first and third balls drawn will be white given that the sample drawn contains exactly 3 white balls?
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