Question
Repeat Problem 67 for the same two capacitors but with themnow connected in parallel.
Step 1
The total capacitance $C$ in a parallel circuit is given by the sum of the individual capacitances, i.e., $C = C_1 + C_2$. Here, $C_1 = 6 \mu F$ and $C_2 = 4 \mu F$. So, $C = 6 \mu F + 4 \mu F = 10 \mu F$. Show more…
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