Question
Repeat the above calculation for an incident virtual photon of mass $k^{2} \equiv-Q^{2}$. Continue to use (6.111). Show that for $\gamma^{*} \mathrm{e}^{-} \rightarrow$ $\gamma \mathrm{e}^{-}$(where $\gamma^{*}$ denotes a virtual photon),$$\overline{|\mathscr{T}|^{2}}=2 e^{4}\left(-\frac{u}{s}-\frac{s}{u}+\frac{2 Q^{2} t}{s u}\right)$$We shall make use of this result in Chapter 10 .
Step 1
The relevant Feynman diagrams involve the exchange of a virtual photon, which we denote as \(\gamma^{*}\). The matrix element can be expressed in terms of the electromagnetic interaction, which is mediated by the photon. Show more…
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