00:03
In the party of this problem, we have to find the gravitational acceleration of a droplet due to the sun.
00:09
When the droplet is on the closest side of the earth, so we need to calculate ac.
00:15
Let's write the formula to calculate this acceleration.
00:18
So ac is equals to gms divided by r square.
00:23
This is our equation number one here.
00:24
This is the gravitational constraint.
00:27
Ms is the mass of the sun and this r is the distance from the center of the sun to the droplet.
00:32
Let's set the values into this equation.
00:34
So ac is equal to 6 .67, multiply by 10, minus 11, newton meter square per kg square into ms, which is equals to 1 .99, multiply by turner as power 30 kg, divide by this r, which is equals to 150, multiply by 10 .50, multiply by 10 .9 ,000 ,000, minus 6 .37 multiplied returners power 6 meter whole square...