Replacing s by (si, s-i) and using the fact that Ki does not actually depend on si, show that Bi

Question

Accepted Answer

First, let's recall the definition of $B_i(s)$ given in Section 7.1.3. It is defined as:

$B_i(s

Replacing $s$ by $\left(s_i, s_{-i}\right)$ and using the fact that $K_i$ does not actually depend on $s_i$, show that $B_i(s)$ given in Section 7.1.3 does not depend on $s_i$. Conclude, therefore, that the definition of $B_i(s)$ is not circular.