Rescue. Your friend (mass 65.0 kg ) is standing on the ice in the middle of a frozen pond. There

Name: Problem 90, Chapter 6: University Physics with Modern Physics
Uploaded: 2021-03-28T06:59:05-08:00
Duration: 1 min 18 s
Channel: Ajay Singhal

Step 1:u000AFirst, we need to find the force applied by you. We can use the formula for force which

Question

Rescue. Your friend (mass 65.0 $\mathrm{kg} )$ is standing on the ice in the middle of a frozen pond. There is very litle friction between her feet and the ice, so she is unable to walk. Fortunately, a light rope is tied around her waist and you stand on the bank holding the other end. You pull on the rope for 3.00 s and accelerate your friend from rest to a speed of 6.00 $\mathrm{m} / \mathrm{s}$ whileyou remain at rest. What is the average power supplied by the force you applied?

   Rescue. Your friend (mass 65.0 $\mathrm{kg} )$ is standing on the ice in the middle of a frozen pond. There is very litle friction between her feet and the ice, so she is unable to walk. Fortunately, a light rope is tied around her waist and you stand on the bank holding the other end. You pull on the rope for 3.00 s and accelerate your friend from rest to a speed of 6.00 $\mathrm{m} / \mathrm{s}$ whileyou remain at rest. What is the average power supplied by the force you applied?

University Physics with Modern Physics

Hugh D. Young 13th Edition

Chapter 6, Problem 90

Instant Answer

Solved by Expert Ajay Singhal

03/28/2021

Step 1

We can use the formula for force which is mass times acceleration. But we don't have the acceleration. We can find it using the formula for acceleration which is final velocity minus initial velocity divided by time. Here, the initial velocity is 0 (because your Show more…

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Rescue. Your friend (mass 65.0 $\mathrm{kg} )$ is standing on the ice in the middle of a frozen pond. There is very litle friction between her feet and the ice, so she is unable to walk. Fortunately, a light rope is tied around her waist and you stand on the bank holding the other end. You pull on the rope for 3.00 s and accelerate your friend from rest to a speed of 6.00 $\mathrm{m} / \mathrm{s}$ whileyou remain at rest. What is the average power supplied by the force you applied?

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Key Concepts

Work-Energy Theorem

This principle states that the work done on an object is equal to the change in its kinetic energy. It connects the force applied over a distance to the resulting increase in the object's energy, making it fundamental in analyzing scenarios where forces cause changes in motion.

Kinetic Energy

Kinetic energy is the energy an object has due to its motion, calculated using the formula KE = 1/2 m v². Understanding kinetic energy is crucial for determining how much work is needed to accelerate an object from rest to a given speed.

Power

Power is the rate at which work is done or energy is transferred. It is defined as the work done divided by the time over which the work is performed, making it essential for evaluating how quickly energy is delivered in a process.

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