00:01
So we have been given this function that shows the weight of female holstained cows at day t, you know, t being the number of days since they've been born.
00:11
And we'd like to know when is this function increasing and when is it decreasing.
00:18
So in order to find increasing and decreasing intervals, our first step is to find the derivative.
00:23
So if i want the derivative of this function, w sub 1 of t, i start 619 is a constant.
00:33
It would be 619 times.
00:35
Well, the derivative of this piece here, i'm going to pull down the 1 .236 times what's in parentheses.
00:49
And i subtract 1 from my exponent times the derivative of what's inside the parentheses.
00:57
So times what's going to be negative 0 .905, e to the negative 0 .002t times times.
01:08
The derivative of that exponent, which is negative 0 .002.
01:14
Okay.
01:16
Let's simplify this slightly.
01:17
We have a lot of constants that we can put together.
01:21
I am multiplying by 619, 1 .236, negative 0 .9, and negative 0 .002.
01:31
Multiplying those all together gives me 1 .3877 times, well, i have an e here, so it's times e to the negative 0 .002t, times my parentheses, 1 minus 0 .905, e to the negative 0 .002t, raised to the 0 .236 exponent.
02:01
Okay, so here's my equation.
02:04
This is the derivative of this function.
02:07
To find where i could be changing from increasing to decrease, or from decreasing back to increasing, i need to know when is the derivative function equal to zero.
02:18
So i want to set this equal to zero and see what values of t that gives me.
02:23
Well, let's examine this piece by piece.
02:27
My constant, and i'll just kind of use red as i walk through here, my constant is positive, so that's not going to give me a zero value.
02:35
E to any power is never going to give me zero.
02:39
It's always going to be positive.
02:40
So i'm not going to get a zero from here.
02:43
So the only way i could get a zero would be for this to equal zero...