00:01
Today we will be finding the average rate of change of a few time intervals based on a table, and we will use the equation average rate of change equals f of b minus f of a over b minus a.
00:09
For the first interval, we have 1 comma 2, and for this one, a is 1, and b is 2.
00:18
So, f of b will be 0 .018, and f of a will be 0 .033, divided by 2 minus 1, and that will give us negative 0 .015 over 1, which is negative 0 .015, and the unit is grams per deciliter over hours.
00:41
For the second one, our intervals 1 .5, comma, 2, and at 1 .5, it's 0 .024, and again, at 2, it's 0 .08.
00:50
So i have 0 .01 minus 0 .024 over 2 minus 1 .5.
01:01
And that will be negative 0 .006 over 0 .5, which will give us negative 0 .012 grams per decilator over hours.
01:13
So the third interval, we have 2 .5, and at 2 .5, it's 0 .012.
01:20
And as 2, it's again, 0 .018.
01:22
So we will have .012 minus 0 .018 divided by 2 .5 minus 2.
01:30
And i'll give us negative .006 over .5, which will be negative .012 grams per deciliter over hours.
01:42
Our last interval is 2 .3, and at 3 it's .007, and net 2 is .018.
01:49
So we'll have .007 minus .018 over 3 minus 2.
01:57
And that will give us negative .011 over 1, which is just .011 grams per deciliter over hours...