00:01
In the given problem here, this is a uniformly charged ring which is having a positive charge spread uniformly over it.
00:17
The magnitude of this charge has been given as q.
00:26
The radius of this ring is a negative charge has been kept a minus q.
00:41
Charge has been kept at its center and started moving it along its axis.
00:49
Suppose at any instant it is shifted to a point p where op is x and it is given that x is very much less than the radius of this ring.
01:04
So at an instant when this charge minus q is at point p, first of all, the electric field the magnitude of electric field at this point p will be, it is given as e is equal to k, q, x divided by x square plus a square to the power 3 by 2.
01:38
But as x is very much less than a, so we can ignore this x here in the denominator.
01:45
So ignoring it here, it becomes k qx divided by a square, just a square, ignoring this x square, raised to the part 3 by 2, or finally, this electric field comes out to be kqx divided by a q.
02:07
The direction of this electric field will be away from the positive charge here.
02:15
So now, when this negative charge is kept at this point b, this negative charge will experience an electrostatic force towards the center.
02:23
Of this ring.
02:26
So that force experienced will be given by minus q times e...