Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Sent to:
  • Textbooks
  • Test Prep
  • Numerade for Schools
  • Bootcamps
  • Class
  • Ask Question
  • StudyParty
  • Earn Money
    Refer a friend. Get $50! Become an Educator
  • Log in

Problem

(a) Suppose that a NASCAR race car is moving to t…

02:21
preview
Numerade Logo

Get the answer to your homework problem.

Try Numerade free for 7 days

Patrick C.
Numerade Educator

Like

Report

Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88

Problem 14 Medium Difficulty

Review Conceptual Example 7 as background for this problem. A car is traveling to the left, which is the negative direction. The direction of travel remains the same throughout this problem. The car's initial speed is $27.0 \mathrm{m} / \mathrm{s},$ and during a 5.0 $\mathrm{s}$ - interval, it changes to a final speed of (a) 29.0 $\mathrm{m} / \mathrm{s}$ and $(\mathrm{b}) 23.0 \mathrm{m} / \mathrm{s}$ . In each case, find the acceleration ( magnitude and algebraic sign) and state whether or not the car is decelerating.

Answer

(a) $a=-0.4 \mathrm{m} \cdot \mathrm{s}^{-2}$
(b) $a=+0.8 \mathrm{m} \cdot \mathrm{s}^{-2}$

Related Courses

Physics 101 Mechanics

Physics

Chapter 2

Kinematics in One Dimension

Related Topics

Motion Along a Straight Line

Discussion

You must be signed in to discuss.
Top Physics 101 Mechanics Educators
Christina K.

Rutgers, The State University of New Jersey

Andy C.

University of Michigan - Ann Arbor

Farnaz M.

Simon Fraser University

Meghan M.

McMaster University

Physics 101 Mechanics Courses

Lectures

Video Thumbnail

04:34

1D Kinematics - Intro

In physics, kinematics is …

Video Thumbnail

07:57

Position - Overview

In mathematics, a position…

Join Course
Recommended Videos

02:16

Refer to Multiple-Concept …

03:47

Multiple-Concept Example 9…

03:04

In preparation for this pr…

06:47

Car $A$ is parked along th…

08:26

A train has a length of 92…

04:40

Constant Acceleration
C…

01:33

Constant Acceleration
F…

02:20

Physics The acceleration o…

06:42

This question concerns the…

01:14

See Sample Problem $\bolds…

08:57

According to recent test d…

03:43

Constant Acceleration
I…

02:47

Review Conceptual Example …

06:39

Consult Multiple-Concept E…

05:01

See Multiple-Concept Examp…

04:49

see Sample Problem $D$ A c…

04:26

An object moves so that it…

01:37

Review Conceptual Example …

07:59

A remote-controlled car is…

03:34

Additional Problems
A c…

Watch More Solved Questions in Chapter 2

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
Problem 64
Problem 65
Problem 66
Problem 67
Problem 68
Problem 69
Problem 70
Problem 71
Problem 72
Problem 73
Problem 74
Problem 75
Problem 76
Problem 77
Problem 78
Problem 79
Problem 80
Problem 81
Problem 82
Problem 83
Problem 84
Problem 85
Problem 86
Problem 87
Problem 88

Video Transcript

So in this problem, we're looking at two scenarios for a car. Um and we're analyzing its motion trying to find the acceleration of the car in two different scenarios. Now, for any of these problems, you always want to start from the same way, which is what you see on the screen in front of you right now. Where for the first part part, eh? I have my five variables for the Kenna Matic equations written down V B, not a tea and acts. Now, when we read through this problem, there's a few things we know for this first set up. First of all, the car is starting out, going 27 meters per second to the west. So this V value will initially be 27 meters per second. Now, over the course of five seconds, so I can fill in my tea value. The car's going to accelerate to 29 meters per second, so it is speeding up as it travels in the westward direction. So for this problem, we now know three unknowns, which is what we want. Because in order to use any of the Kinnah Matic equations you see on the right side of the screen. You need to know three of them in order to find 1/4. And the way we pick which of these equations we want to use is by looking at what piece of information we want to know and what piece of information we currently do not have and also don't need to find. So right now, the problems asking for us to find acceleration, which means the variable we don't know and don't need to know is displacement this X value. So the one I just crossed out the ex that tells us which equation to use because when we look over at the Cannes A Matic equations were going to use whichever one does not use the Letter X. And so these three all have acts featured prominently in them, Which means our equation for this first problem is going to be that top equation. The V equals V not plus 80. Um, before we solve this since this one and part B are both looking for acceleration and actually going to rearrange this equation to find what acceleration is equal to. So we have the minus V not equals 80 NFL divide both sides by t you end up with the acceleration equation of V equals or a equals V minus B not divided by Todd. So let's go ahead and plug our numbers in here. Um, for part ay, that gives us 29 minus 27 divided by the time of five. And when we plugged that in, we get an acceleration of 0.4 meters per second squared. Okay. And that is part A. So there's a small positive acceleration for part A. Um, let's look at what we're doing for part B here in the second group I have. So the starting conditions are actually the same. We have 27 meters per second is the starting speed and it also happens over a five second interval. But this time we're slowing down to 23 meters per second. Now the first thing that should be apparent is in the first case, we were accelerating. We were speeding up from 27 to 29 in part be here. We're actually slowing down. We're decelerating from 27 meters per second to 23 meters per second. Um, so we should expect our acceleration to come out as a negative value. In addition to that, um, we should also expect it to be a larger number, a bigger magnitude acceleration, because I'm actually losing four meters per second where before I was gaining too. So the magnitude of this change is bigger. So when I plug in my numbers, I have 23 my final minus 27 my initial divided by five. And this gives us a negative 0.8 meters per second squared, meaning it is slowing down, um, and reducing its speed by that much. And our predictions held out, it is both a negative value, meaning it is slowing down, and it is a larger magnitude than part.

Get More Help with this Textbook
John D. Cutnell, Kenneth W. Johnson

Physics

View More Answers From This Book

Find Another Textbook

Related Topics

Motion Along a Straight Line

Top Physics 101 Mechanics Educators
Christina K.

Rutgers, The State University of New Jersey

Andy C.

University of Michigan - Ann Arbor

Farnaz M.

Simon Fraser University

Meghan M.

McMaster University

Physics 101 Mechanics Courses

Lectures

Video Thumbnail

04:34

1D Kinematics - Intro

In physics, kinematics is the description of the motion of objects and syste…

Video Thumbnail

07:57

Position - Overview

In mathematics, a position is a point in space. The concept is abstracted fr…

Join Course
Recommended Videos

02:16

Refer to Multiple-Concept Example 5 to review a method by which this problem…

03:47

Multiple-Concept Example 9 illustrates the concepts that are pertinent to th…

03:04

In preparation for this problem, review Conceptual Example 7 From the top of…

06:47

Car $A$ is parked along the northbound lane of a highway, and car $B$ is tra…

08:26

A train has a length of 92 $\mathrm{m}$ and starts from rest with a constant…

04:40

Constant Acceleration
Cars $A$ and $B$ move in the same direction in adja…

01:33

Constant Acceleration
Figure $2-27$ shows a red car and a green car that …

02:20

Physics The acceleration of an object is a measure of how much its velocity …

06:42

This question concerns the motion of a car on a straight track; the car'…

01:14

See Sample Problem $\boldsymbol{B}$ A car traveling in a straight line has a…

08:57

According to recent test data, an automobile travels 0.250 $\mathrm{mi}$ in …

03:43

Constant Acceleration
In Fig. $2-27,$ a red car and a green car, identica…

02:47

Review Conceptual Example 5 before beginning this problem. You are traveling…

06:39

Consult Multiple-Concept Example 11 in order to review a model for solving t…

05:01

See Multiple-Concept Example 9 for the basic idea behind problems such as th…

04:49

see Sample Problem $D$ A car starts from rest and travels for 5.0 s with a u…

04:26

An object moves so that its position changes in the following way: $x(t)=-10…

01:37

Review Conceptual Example 16 as background for this problem. The water skier…

07:59

A remote-controlled car is moving in a vacant parking lot. The velocity of t…

03:34

Additional Problems
A car moving with constant acceleration covered the d…

Additional Physics Questions
a-bicyclist-makes-a-trip-that-consists-of-three-parts-each-in-the-same-direction-due-north-along

04:30

A bicyclist makes a trip that consists of three parts, each in the same dire…

a-suppose-that-a-nascar-race-car-is-moving-to-the-right-with-a-constant-velocity-of-82-mathrmm

02:21

(a) Suppose that a NASCAR race car is moving to the right with a constant ve…

a-motorcycle-has-a-constant-acceleration-of-25-mathrmm-mathrms2-both-the-velocity-an

02:30

A motorcycle has a constant acceleration of 2.5 $\mathrm{m} / \mathrm{s}^{2}…

due-to-continental-drift-the-north-american-and-european-continents-are-drifting-apart-at-an-averag

02:40

Due to continental drift, the North American and European continents are dri…

two-soccer-players-start-from-rest-48-mathrmm-apart-they-run-directly-toward-each-other-both

06:37

Two soccer players start from rest, 48 $\mathrm{m}$ apart. They run directly…

the-three-toed-sloth-is-the-slowest-moving-land-mammal-on-the-ground-the-sloth-moves-at-an-average

03:41

The three-toed sloth is the slowest-moving land mammal. On the ground, the s…

a-mountain-climbing-expedition-establishes-two-intermediate-camps-labeled-a-and-b-in-the-drawing-a

05:52

A mountain-climbing expedition establishes two intermediate camps, labeled A…

ssm-two-trees-have-perfectly-straight-trunks-and-are-both-growing-perpendicular-to-the-flat-horizont

02:41

SSM Two trees have perfectly straight trunks and are both growing perpendicu…

one-afternoon-a-couple-walks-three-fourths-of-the-way-around-a-circular-lake-the-radius-of-which-i

03:45

One afternoon, a couple walks three-fourths of the way around a circular lak…

a-boeing-747-jumbo-jet-has-a-length-of-597-mathrmm-the-runway-on-which-the-plane-lands-inter

04:00

A Boeing 747 Jumbo Jet has a length of 59.7 $\mathrm{m}$ . The runway on whi…

Add To Playlist

Hmmm, doesn't seem like you have any playlists. Please add your first playlist.

Create a New Playlist

`

Share Question

Copy Link

OR

Enter Friends' Emails

Report Question

Get 24/7 study help with our app

Available on iOS and Android

About
  • Our Story
  • Careers
  • Our Educators
  • Numerade Blog
Browse
  • Bootcamps
  • Books
  • Topics
  • Test Prep
  • Ask Directory
Support
  • Help
  • Privacy Policy
  • Terms of Service
Get started