00:01
So in this problem, we are dealing with static electric fields and the relationship between the electric force and some other forces involved with the electrostatic force, like in this problem where the force of the elastic spring is involved in the relationship with the electrostatic repulsive force.
00:24
So we have two blocks and they are basically repulsing each other, repelling each other one from another because they have the same charge q and the same sign of the charge.
00:35
Now the total force between the two blocks can be modeled as the force between two point charges that are pulling each other one from another because we are assuming that the distance between two blocks is large enough so that you can treat them like two point charges.
00:54
And since we're given that l, being l is a separation between two blocks, the electrostatic force is static constant, q squared over l squared.
01:09
Now this force must balance another force, which is the elastic force of the spring, which will be stretched by the acceleration and the motion resulting from the acceleration of the two blocks coming from the electrostatic force repulsion.
01:29
So this force of corresponding to the spring stretching is x.
01:37
Now according to the k is the spring constant and x is the horizontal stretch because we are placing the two blocks to be on the horizontal axis in our coordinate system.
01:52
So from this condition that fe must equal fs in order for this problem to satisfy the static condition, we can directly substitute and say, okay, this is kx equal this expression right here.
02:15
And directly we can say that q squared equals and basically kx times l squared over electrostatic.
02:28
Constant.
02:30
From here we know that q is equal to the square root of k x times cell squared over electrostatic constant...