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Review solving systems of three equations in three unknowns.Solve.$$\begin{aligned}x+y+z &=3 \\x-y+z &=1 \\-x-y+z &=-1\end{aligned}$$
Step 1
Step 1: First, we add the first two equations together to eliminate the variable $y$: $$ \begin{aligned} (x+y+z) + (x-y+z) &= 3 + 1 \\ 2x + 2z &= 4 \end{aligned} $$ Simplifying this gives us $x + z = 2$. Show more…
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