00:01
So in this example, i'm given an equation of our parabola that opens sideways.
00:07
Then we're going to convert this equation to our other form.
00:11
So we can easily see the vertex, and we're going to use those data points to graph it.
00:15
So the first thing when we're converting is we're going to complete the square, but we can't do that really unless the y squared has a 1 as a coefficient.
00:22
So i need to divide this negative 4 so that we can get that 1 y squared we're looking for.
00:28
We always have to do things on both sides.
00:30
And in the end, we'll end up multiplying that 4 back.
00:33
So don't worry about any fractions or other issues for now.
00:37
So this will become a y squared, negative 8 divided by negative 4 is 2, and 10 divided by 4.
00:46
We can actually just leave it like that for now.
00:52
Okay.
00:53
So from here, we're going to group these first two terms.
00:56
We're going to figure out what to add to make that a perfect square.
00:59
So our shortcut to determine that is we can take this middle, b value, and divide it in half.
01:05
So 2 divided by 2 is 1, and then we square that value.
01:09
So 1 squared is 1.
01:11
So that means if i add 1, i'm going to end up with a perfect square, so i'm going to go ahead and do that.
01:16
But if i add one on the same side, i also need to subtract one to make sure that they zero out, and i'm not really changing my equation.
01:23
Now what this lets me do is factor this trinomial.
01:26
So i'm going to keep the x over negative 4.
01:29
This trinomial is going to factor is y plus 1 squared, plus we have 10 over 4 minus...