00:01
Hi there, so for this problem we have an infinite plain slab of thickness 2 times d that carries an uniform volume charge density row.
00:13
Now we need to find the electric field as a function of y, where y is equal to zero at the center, and we also need to plot the electric field versus y, calling the electric field positive when it points in the positive.
00:30
Direction and negative when it points in the minus y direction.
00:36
So in this case, we know that on the s -seat plane, the electric field is equal to zero by symmetry.
00:52
So for this case, because of this geometry, we need to set up a gaussian bill pops with one phase in this plane.
01:03
And the other at y, as is shown as follows, as is shown in this figure right here.
01:16
So with that said, if we use gauss law, we obtain that the integral of the product between the electric field and the differential area is equal to their magnitudes.
01:31
We can take out the electric field because it is a constant and we will have the integral of the differential area, which is the total area.
01:42
And then this by gauss law, we know that that is the enclosed charge divided by epsilon sub -0.
01:48
And we know that we can write the enclosed charge as the area times y, this thickness in here, and this times the density charge row...