00:02
Our question says that we have an individual named nicardo of mass 80 kilograms, and i represent that as m sub r.
00:11
Another individual named carmelita, who is lighter, and they're in joining them.
00:16
In a canoe, that's 30 kilograms.
00:19
I label the canoe, m sub b.
00:22
I do that just to avoid confusion because i'm going to use m sub c to represent carmelita.
00:28
So m sub b, canoe, it's very similar, so i use m sub b to represent the canoe.
00:34
When the canoe is at rest, water, they are going to switch seats.
00:37
And these seats are three meters apart, which i label as l, and symmetrically located with respect to the canoe center.
00:45
So the canoe center is l over two.
00:48
If the canoe moves 40 centimeters horizontal relative to peers post, what is the mass of carmelita? okay.
00:55
So i say that the distance the canoe moves, which i call d, is equal to 40 centimeters or 0 .40 meters.
01:01
I change it into meters, so that way it and the length of the canoe are both in the same units and the units of meters, and we're sticking with si units there.
01:10
Okay, so we're going to let the center amass of the two -person system, and it's assumed to be closer to ricardo because it says he's bigger, be a distance that we're going to call the canoe of length l, right? so we can write that as the mass of ricardo, times l over 2 minus x, right, is equal to the mass of the boat times x plus the mass of carmelita times l over 2 plus x...