Question
Right-triangle relationships Draw a right triangle to simplify the given expressions. Assume $x>0.$$$\sin \left(2 \cos ^{-1} x\right)(\text { Hint: Use } \sin 2 \theta=2 \sin \theta \cos \theta$$
Step 1
We can apply this identity to our given expression, $\sin \left(2 \cos ^{-1} x\right)$, to get: $$\sin \left(2 \cos ^{-1} x\right) = 2\sin \left(\cos ^{-1} x\right) \cos \left(\cos ^{-1} x\right)$$ Show more…
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