Rocket Motion Suppose a small single-stage rocket of total mass $m(t)$ is launched vertically and that the rocket consumes its fuel at a constant rate. If the positive direction is upward and if we take air resistance to be linear, then a differential equation for its velocity $v(t)$ is given by
$$
\frac{d v}{d t}+\frac{k-\lambda}{m_{0}-\lambda t} v=-g+\frac{R}{m_{0}-\lambda t^{\prime}}
$$
where $k$ is the drag coefficient, $\lambda$ is the rate at which fuel is consumed, $R$ is the thrust of the rocket, $m_{0}$ is the total mass of the rocket at $t=0$, and $g$ is the acceleration due to gravity. See Problem 21 in Exercises $1.3$.
(a) Find the velocity $v(t)$ of the rocket if $m_{0}=200 \mathrm{~kg}$, $R=2000 \mathrm{~N}, \lambda=1 \mathrm{~kg} / \mathrm{s}, g=9.8 \mathrm{~m} / \mathrm{s}^{2}, k=3 \mathrm{~kg} / \mathrm{s}$, and
$v(0)=0$
(b) Use $d s / d t=v$ and the result in part (a) to find the height $s(t)$ of the rocket at time $t$.