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Rocket obscrvations show that dust particles in Earth's upper atmosphere are often clectrically charged. (a) Find the distance separating two dust particles if each has a charge of $+e$ and the Coulomb force between them has magnitude $1.00 \times$ $10^{-14} \mathrm{N}$ . (b) Calculate the mass of one of the dust particles if this Coulomb force would accelerate it at $4.50 \times 10^{8} \mathrm{m} / \mathrm{s}^{2} .$ (In the upper atmosphere, effects from other nearby charges typically result in a small net force and acceleration.)

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Numerade Educator

University of Washington

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University of Sheffield

but a off the given problem for from a cool ums law, the force is, ah equal to K tones for two charged particles, each having a plus he and plus so the productive charges will be e square, derided by the distance between them which is our square from here will finds distance so the distance will be our physical too square root off soldering for our this will be screwed off a k e squared divided by force will substitute the values for K E and F So okay, he's a nine times 10 to the power nine times charge on each particle is 1.6 times don't power minus 19 2 lumps square divided by the force given here is one times 10 to the power minus 14 Newton. This gives us the distance between the particles off 1.51 time standard of power minus seven meters. But me, we can find the mass of the particle using Newton. Second love motion, that is a force is proportional to the Maas. I'm exploration so mass will be equal. Thio force the right by acceleration force giving these a onetime stuntman power minus 14 Newton divided by exploration for 0.5 times 10 to the power eight. This gives us the moss off a particle to be 2.22 times 10 to the power minus 23 kg.