00:01
Okay, so the question was asking us to determine the speed of baker that is relative to the observer.
00:06
While we know we can come out of such an equation, which is vab equal to vao plus bbo over 1 plus val times vbo over c square.
00:17
Okay, so bab is the speed of able that is relative to the baker, and val is the speed of able that is relative to the earth observer.
00:30
So our question is asking us to find out vbo, which is the speed of a baker that is relative to the earth observer.
00:37
So if we plugging the value of vab and vho, we'll have 0 .114 is equal to 0 .4 o 'o plus vbo over 1 plus 0 .4 .4 oc times v0 and then over c squared okay and you can move 1 plus 0 .4 oc times vb o over c square to the left side therefore we have 0 .114c times 1 plus 0 .4 oc times vb o over c square is equal to 0 .40 c plus bbo over c squared is equal to 0 .404 c plus bbo okay, if we expand it, we'll have 0 .114c plus 0 .114c times 0 .40c times vbo over c squared is equal to 0 .404c plus vbo.
02:40
And as you can tell on the left side, you can tell the c can be cancelled in this case.
02:44
Okay.
02:48
And then we'll have 0 .114c plus 0 .114 times 0 .40 times vbo is equal to 0 .40c plus vbo.
03:12
Okay, and then we could have, let's move vbo, ovbo on the left side, and then we'll have 0 .114 times 0 .40 times vbo minus vbo.
03:40
Okay, because i move the vbo from the right side to the left side.
03:45
And then it would be equal to 0 .404 .00c minus 0 .0...