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Hi, here in this given problem to show the applied forces, first of all we draw the geographic directions.
00:10
Geographic directions which include north -south along vertical, east -west along horizontal.
00:19
Now the first force f a having a magnitude of 2240 newton and it is at an angle of 34 degree south of east like this.
00:41
This is f a at an angle of 34 .0 degree.
00:48
Then the second force magnitude of the second force f b, this is 3160 newton and this is due east like this.
01:13
This f b is a little more than f a.
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So we should reduce the length of this f a.
01:23
Suppose this is f a up to here only.
01:26
Now we have to find resultant of the two forces using component method.
01:31
So we resolve this f a into two components.
01:34
Horizontal component will be f a cos 34 degree and its vertical component along negative y axis or due south that is f a sin 34 degree...