Question

Roses Graph the roses $r=\cos m \theta$ for $m=1 / 3,2,3$, and 7 .

   Roses Graph the roses $r=\cos m \theta$ for $m=1 / 3,2,3$, and 7 .
University calculus: early transcendentals (Global Edition)
University calculus: early transcendentals (Global Edition)
Joel Hass, George… 3rd Edition
Chapter 10, Problem 33 ↓
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Roses Graph the roses $r=\cos m \theta$ for $m=1 / 3,2,3$, and 7 .
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Transcript

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00:01 In this video, we're going to go through the answer to question number 37 from chapter 11 .4.
00:05 So it has to plot the functions r equals cause of m theta for m equals a third, two, three, and seven.
00:15 Firstly, for m equals a third.
00:29 So one thing to note about all of these curves is that because it's r equals cause of something, we know that cos is an even function.
00:41 So cause of minus theta is equal to cos of theta.
00:45 So therefore we have x -axis symmetry in all of these curves.
00:55 So starting with m equals a third, let's think about some easy to calculate values and put them in a table first.
01:04 So theta and arc.
01:07 When theta is equal to zero, r is equal to one.
01:14 When theta is equal to pi by 2, r is equal to cos of pi by 6, which is equal to root 3 over 2, which is around about 0 .9.
01:37 When theta is equal to pi, r is equal to, well, it's cos of pi by 3, which is half.
01:51 And when theta is equal to 3 pi by 2, then r is equal to cause of pi by 2, which is just 0.
02:08 And when theta is equal to 2 pi, r is equal to cos of 2 pi by 3, which is minus a half.
02:27 Which takes us back to that.
02:33 So we can keep going with more values of theta, but we know that we have x -axis symmetry, so i think we've got all we need right now.
02:43 So starting from here, we just join the points up in order.
02:52 And then that's where we've got two.
02:54 But now we can just reflect that in the x -axis, and that is the curve for r equals cos of theta over three.
03:17 Next up is equal to two.
03:24 Again, we're going to have x -axis symmetry, but let's draw some axes and calculate some known values.
03:41 When theta is equal to zero, r is equal to 1.
03:44 Let's try when theta is equal to pi by 8.
03:50 Then we've got r equals cos of pi by 4, which is root 2, over 2, which is around about 0 .7.
03:59 So that's r equals 1 here, pi by 8, then r is equal to 0 .7.
04:13 Then r is going to be equal to cos of pi by 2 which is 0, 3 pi by 8, which is along here, then cost is going to be equal to, sorry, r is going to be equal to minus root 2 over 2.
04:37 So that brings us down here.
04:44 What about pi over 2? well, in that case, r is going to be equal to cos of pi, which is minus 1.
05:00 That takes us down here.
05:11 Then what about 5 pi by 8? that's going to be minus root 2 over 2 again.
05:21 So 5 pi by 8 is this one.
05:24 So minus takes us down here, minus root 2 over 2.
05:31 What about 3 pi by 4? that's going to be 0.
05:40 And then 7 pi by 8, that's going to be root 2 over 2, which takes us there...
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