Question
Rubidium- 87 , which forms about $28 \%$ of natural rubidium, is radioactive, decaying by the emission of a single beta particle to strontium-87. Write the nuclear equation for this decay of rubidium-87.
Step 1
Rubidium-87 has an atomic number of 37 (since it's rubidium) and a mass number of 87. Show more…
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The naturally occurring isotope rubidium-87 decays by beta emission to strontium- 87 . This decay is the basis of a method for determining the ages of rocks. A sample of rock contains $102.1 \mu \mathrm{g}{ }^{87} \mathrm{R} \mathrm{b}$ and $5.0 \mu \mathrm{g}{ }^{87} \mathrm{Sr}$. What is the age of the rock? The half-life of rubidium- 87 is $4.8 \times 10^{10} \mathrm{y}$
The naturally occurring isotope rubidium- 87 decays by beta emission to strontium- 87 . This decay is the basis of a method for determining the ages of rocks. A sample of rock contains $102.1 \mu \mathrm{g}^{87} \mathrm{Rb}$ and $5.3 \mu \mathrm{g}^{87} \mathrm{Sr}$. What is the age of the rock? The half-life of rubidium- 87 is $4.8 \times 10^{10} \mathrm{y}$.
Rubidium-87 is radioactive, decaying by the emission of a single beta particle. Write the nuclear equation for this decay.
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