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Running with an initial velocity of $+9.2 \mathrm{m} / \mathrm{s},$ a horse has anaverage acceleration of $-1.81 \mathrm{m} / \mathrm{s}^{2}$ . How much time does it takefor the horse to decrease its velocity to $+5.5 \mathrm{m} / \mathrm{s} ?$

time elapsed $t=2.044 \mathrm{s}$

Physics 101 Mechanics

Chapter 2

One-Dimensional Kinematics

Motion Along a Straight Line

Priscila T.

February 19, 2021

why the 3.7 is positive if -9.2 is negative

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So in this problem we have our horse with initial velocity initial velocity of 9.2 meters per second and he has average acceleration off miners. One point 81 meters per second squared. Uh, the problem wants to know. How much time does it take so we can get a velocity off 5.5 meters per seconds? Okay. How do we solve this? We know. Resists equation, relate velocity with time. You just need to use a creation. V equals zero plus a times teeth. So the fine of velocity is five point five equals the initial velocity 9.2 minus one point 81 two So 5.5 miners 9.2 minors tree 0.7. It crossed two minus one point. Do you want three d? We can't. Good sign. Then we have that time. It's going to be 3.7. Divided by one point 81. This is precisely 2.0 for for seconds. Staying, sir. Thanks for watching

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