running-with-an-initial-velocity-of-92-mathrmm-mathrms-a-horse-has-an-average-acceleration-of-181-ma

Question

Running with an initial velocity of $+9.2 \mathrm{m} / \mathrm{s},$ a horse has an
average acceleration of $-1.81 \mathrm{m} / \mathrm{s}^{2}$ . How much time does it take
for the horse to decrease its velocity to $+5.5 \mathrm{m} / \mathrm{s} ?$

Nathan Silvano · Accepted Answer

So in this problem we have our horse with initial velocity initial velocity of 9.2 meters per second and he has average acceleration off miners. One point 81 meters per second squared. Uh, the problem wants to know. How much time does it take so we can get a velocity off 5.5 meters per seconds? Okay. How do we solve this? We know. Resists equation, relate velocity with time. You just need to use a creation. V equals zero plus a times teeth. So the fine of velocity is five point five equals the initial velocity 9.2 minus one point 81 two So 5.5 miners 9.2 minors tree 0.7. It crossed two minus one point. Do you want three d? We can&#x27;t. Good sign. Then we have that time. It&#x27;s going to be 3.7. Divided by one point 81. This is precisely 2.0 for for seconds. Staying, sir. Thanks for watching

Donald Albin · Answer

All right. I&#x27;m gonna use the equation V squared equals B initial squared um Plus to a delta X. So, V is 11.5 m/s. Initial is zero. So then I have to A Delta X. and Delta X is 18. Well, two times 18 is 36. That would be 36 a dividing by 36 on both sides. I get a is 11.5 over 36. Let me use a calculator for that. Mhm. Oops. Yeah. 11.5 Divided by 36 Would be 0.3 19 meters per second. Okay, lets do part B. How long did it take her to reach a top speed? Well, V which is 11.5 is going to equal be initial plus A times T. So T is just going to be 11.5 divided by .319. So where am I? Here we go? I forgot to square it. Sorry about that B squared equals V initial squared Plus two adult axe. So that needs to be 11.5 square thought something wasn&#x27;t right there. Okay, so back to this 11.5 where 3.67. That makes more sense. Alright, now we move on to here. Um So again, it&#x27;s that divided by 3.67. So v equals 80 11.5, divided by 3.67. Okay, Gives me 3.13 seconds. Mm.

Matthew Lueckheide · Answer

All right. So this horse Secretariat ran the Kentucky Jerry, which is 1.25 miles long in a minute and 59.2 seconds. And we have to convert. Um, we have to use the distance and the time to get an average speed. Um, off Secretariat during the race, in meters per seconds. Eh? So I didn&#x27;t think the quickest thing to do is convert this minute and second time into just seconds. Right. So there&#x27;s 60 minutes in. Sorry there. 60 seconds in one minutes, We&#x27;re gonna add 60 to 59.2 seconds. So this total time is going to be 100 and 19.2 seconds. Now, we got to convert, um, 1.25 miles in two meters, which we&#x27;re going to do through the yard. Right, So we can use the conversion factor of 1760 yards over one mile, and then we can go. One meter is equal to 1.94 Both of these unit conversions are in the textbook on the first chapter. Right. So when you get that answer, I&#x27;m gonna take this out to a few decimal places to be safe. You got to thousands and 10.969 meters. Right. And then we have the velocity are sorry. We have the ah, the amount of time it took to run that distance on Dhe. So we&#x27;re gonna divide that by 100 19.2 seconds and our final answer rounded to three significant figures from, ah, 1.25 miles. And that&#x27;s going to give us 16 16.9 meters per seconds.

Patrick Connors · Answer

Okay, so in this problem, we&#x27;re working with two bicyclists that are in a race. Our 1st 1 is the leader and the 2nd 1 is playing catch up. Now we know that the leader is traveling at a rate of 11.1 meters per second and that this is a constant velocity, meaning the acceleration is zero meters per second squared. The racer who&#x27;s playing catch up is starting at a slower rate of 9.5 meters per second and his acceleration is 1.2 meters per second squared. Now the questions asking us, How long will it take for the person playing catch up to catch the leader? So the time is going to be the same value, but the leader is 10 meters in front of the person playing catch up. This means that however far the leader travels, the person playing catch up has to travel that far, and they have to travel 10 additional meters because they&#x27;re trying to make up that distance between them. So for both of these equations, we do not know anything about the final velocity. So the Kinnah Matic equation we&#x27;re going to be using to solve them is that last one there because it does not have the final velocity in it. So let&#x27;s do the leaders equation first, Um, his ex value is X equals V, not T. So 11.1 multiplied by time, plus 1/2 A T squared. Now the nice thing here is there&#x27;s no acceleration for the leader. So this is actually the end of that equation, and this gives us a nice term for acts that we can use to substitute in to the person playing catch up. So switching over to the second person&#x27;s equation, going with the same one the X equals V, not t plus 1/2 A t squared instead of acts. I have acts plus 10 equals the initial velocity multiplied by time plus 1/2 A T squared, which gives us 0.6 t squared. Now, at this point, I&#x27;m gonna combine my two separate equations because my first equation one for the leader told me that X is the same thing. Is 11.1 tea so I can take that value and use the substitution principle to put it in there, and that gives us our combined equation. Change colors one more time here of 11.1 T plus 10 equals 9.5 T plus 0.6 t squared. Now, looking at this, we hopefully notice that this is set up more or less like a quadratic equation where we have a T squared value, a t value and one term with no tea at all. So I&#x27;m going to rearrange it to set it up to look exactly like a quadratic. We end up with zero equals 0.6 t squared, minus 1.60 minus 10. Now, we&#x27;re gonna need to use the quadratic formula to solve this. Before I do that, I like to make sure my A term is equal to one. So I&#x27;m gonna divide everything by that 0.6 and we get zero equals T squared minus 2.7 70 minus 16.7. And now that it&#x27;s in kind of that basic quadratic form, we can take this and plug it into the quadratic equation. So that gives us what we follow along with the equation listed here that are X value, which in this case that&#x27;s well, confusing. Let me change attacks. What we&#x27;re finding which is our time is equal to the opposite of be so. 2.67 plus or minus radical that b squared minus four A. C. So four times a which is one time see which is negative. 16.7 all over, two times a, which is just too so going through this one step at a time. In our calculator, this reduces to 2.67 plus or minus 8.59 divided by two. And here we end up with two time values, one of which is positive, one of which is negative. We actually only care about the positive value because the time has to happen in the positive part, not the negative part, because he catches him after the timer starts. Not before it starts, and we end up with a time of 5.6 seconds.

Nathan Silvano · Answer

So problem 31. We have a runner generates our acceleration 1.9 meters per second squared during a time of five points too seconds. The problem also say&#x27;s there he begins arrest. That means his initial velocity zero it and then after 5.2 seconds is a celebration goes to zero. Okay, so first I think of the problem, we need to discover the velocity after runner and time. Close to seconds. Okay. T equals two. It&#x27;s under the period of acceleration. So we need to consider the acceleration to discover the velocity A runner. And how is it going to do this? We know that the Reza equation that relate velocity which time there is the tiny show velocity loss separation times t Using desecration, we can discover the velocity. So velocity this vehicle zero That is the initial velocity plus acceleration 1.9 times two. This is going to be three point eight meters per second. That is the velocity of the runner in T equals two seconds. And the second item we need to know the final velocity off the runner. The velocity of the end of the race. We know that after 5.2 seconds. Iran. It don&#x27;t accelerate it anymore. So he reaches his maximum speed in 5.2 seconds. And then the speed becomes constant onto the end of the race. So we just need to use the same equation. V equals zero plus a time Steve and used the time when he reaches the master move speed that is V equals syrup, plus 1.9 times five points to. So finally, the final velocity develops that you have the end of the race of the governor going to be 9.8 eight meters per second. But the final answer. Thanks for watching.

Wesley Hines · Answer

so as mentioned in the textbook, final velocity is equal to initial velocity, the acceleration times time. So we want to reach a final velocity of 22 meters per second and we know that it started from rest and that means that&#x27;s initial velocity was zero and we&#x27;re given that the acceleration is that one meters per second squared now From here we just sell for tea by dividing 22 by 1.7 and this will give us a total time needed of 12.94 seconds.

Problem

Predict/Calculate Assume that the brakes in your …

Problem 36 Easy Difficulty

Running with an initial velocity of $+9.2 \mathrm{m} / \mathrm{s},$ a horse has an
average acceleration of $-1.81 \mathrm{m} / \mathrm{s}^{2}$ . How much time does it take
for the horse to decrease its velocity to $+5.5 \mathrm{m} / \mathrm{s} ?$

Answer

time elapsed $t=2.044 \mathrm{s}$

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