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($S$)-(-)-2-Methyl-1-butanol can be converted to (+)-2-methylbutanoic acid without breaking any of the bonds to the asymmetric center. What is the configuration of ( $-$ )-2-methylbutanoic acid?
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This means that the configuration of the asymmetric center remains the same during the conversion. Show more…
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(S)-(-)-2-Methyl-1-butanol can be converted to (+)-2-methylbutanoic acid without breaking any of the bonds to the asymmetric carbon. What is the configuration of (-)-2-methylbutanoic acid? SOLUTION We know that ( + )-2-methylbutanoic acid has the relative configuration shown because it was formed from ( S )-(-)-2-methyl-1-butanol without breaking any bonds to the asymmetric carbon. Therefore, we know that ( + )-2-methylbutanoic acid has the S configuration. We can conclude then that (-)-2 -methylbutanoic acid has the R configuration.
The reaction of ( $R$ )-1-iodo-2-methylbutane with hydroxide ion forms an alcohol without breaking any bonds to the asymmetric center. The alcohol rotates the plane of polarization of plane-polarized light counterclockwise. What is the configuration of ( + )-2-methyl-1-butanol?
Complete the mechanism for the reaction of 2-butanol in sulfuric acid at 140 °C by adding any missing atoms, bonds, charges, nonbonding electrons, and curved arrows. Note the use of a generic alcohol to represent another 2-butanol introduced in panel three.
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