00:03
In this question, p .k.
00:06
Of saccharine, which is a weak acid, given as 2 .32.
00:13
Also, initial concentration is given as 0 .25 molar, and we have to find out the ph and this reaction, ionizing reaction also given.
00:26
So let's make the ice table.
00:45
Here, initial concentration is 0 .25.
00:50
And this one zero, zero, change concentration minus x, x, x, and equilibrium concentration, 0 .25 minus x, x, x.
01:07
Okay, now let's do one thing up here.
01:11
P, ka given.
01:12
Pka means minus log ka is 2 .32.
01:18
So, k .a.
01:20
Will be 10 to the power negative 2 .32.
01:26
And the value is 0 .0048.
01:31
That is 4 .8 times 10 to the power negative 2.
01:36
Okay, this is the value of ka we already got.
01:40
Now, we'll write down the expression for ka here.
01:47
Ka.
01:48
Is concentration of h3o plus times in c7h4 so3 minus divided by the concentration of saccharine...