Question
Samarium-151 is a beta emitter. Write an equation for this nuclear reaction and identify the product nucleus.
Step 1
In beta decay, a neutron in the nucleus is converted into a proton, and an electron (beta particle) and an antineutrino are emitted. The atomic number of samarium is 62, so it has 62 protons. The mass number of samarium-151 is 151, which means it has 151 nucleons Show more…
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