00:01
In the given question, we have to calculate the pressure of benzene if the moles are one, okay, for a molar volume.
00:08
The volume is provided us as 2 liter.
00:10
The moles are 1.
00:12
Okay.
00:13
And we have to calculate this pressure utilizing the redlich -kion equation, which is p equals to nrt, v minus n b minus n square a under root t, 1 upon v, v, v plus n -n -r -t.
00:30
B.
00:31
Okay.
00:31
So we have been provided the temperature also that is t which is equal to 595 kelvin.
00:38
So we have to determine the pressure of benzene using this equation and we have to at the end determine what are the forces between the benzene are they attractive or they repulsive.
00:50
The value of a constant is provided us as 452 bar decometer to the power 6 mole minus 2 kelvin 1 by 2 and the value of constant b is given as 0 .0 8271 decameter cube mole inverse.
01:13
Now this pressure we are referring as pr and to calculate that we also need the value of this gas constant r.
01:22
So the value of capital r which is the universal gas constant is 0 .0 .831 decameter cube bar kelvin inverse, mole inverse, okay? so whenever our volume is in decameter cube and the pressure is in bar, we use the value of universal gas constant as 0 .0831.
01:44
So we can calculate this pr, moles are 1, gas constant 0 .0831 into our temperature that is 595 upon volume that is provided us as 2 liter.
02:00
Okay so 2 liter is also equal to 2 decameter cube okay 1 liter is equal to 1 degameter cube so we can use 2 liter as 2 decameter cube okay so volume is 2 over n that is the mole is 1 the value of b is 0 0 8271 subtracting n square 1 square a is 452.
02:28
Root temperature means root 595 into 1 upon v that is 2.
02:33
2 plus nb once again 1 into the value of b is you can write it here.
02:40
This is our 2 into 2 plus 1 into 0 .08271...