This means that the final volume $V_2$ is twice the initial volume $V_1$. We can write this as:
\[V_2 = 2V_1\]
Substituting the given value of $V_1 = 0.860 \, \text{ft}^3/\text{lbm}$, we get:
\[V_2 = 2 \times 0.860 = 1.720 \, \text{ft}^3/\text{lbm}\]
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