00:01
Hello, so we're given here that our mean mu is equal to 72 .7 where our standard deviation is 13 .1, and our sample size n is 38.
00:12
So for part a, we want to standardize using the z score.
00:16
So for 70, we have z sub 1 is going to be, so 70 minus 72 .7 over 13 .1 is approximately negative 0 .206.
00:30
And then for 80, our z score, z sub 2, is going to be 80 minus 72 .7 divided by 13 .1, which is approximately 0 .557.
00:44
And then we use the z table here to find the probability that z is less than both of these values.
00:50
And then we're going to get that the probability that z is between or x between 70 and 80 is going to work out to be 0 .71.
01:00
Minus 0 .418.
01:03
And that's going to give us about 0 .293 or 293%.
01:10
And then for part b, for the z scores, so for 70, we have z1 is going to be 70 minus 72 .7, divided by now 2 .14...