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See Example 3.Air Travel. An airplane flew from Chicago to San Francisco in 3.75 hours. If the cities are $1,950$ miles apart, what was the average speed of the plane?
$520$ miles per hour
Precalculus
Algebra
Chapter 2
Equations, Inequalities, and Problem Solving
Section 4
Formulas
Algebra Topics That are Reviewed at the Start of the Semester
Equations and Inequalities
Missouri State University
Oregon State University
Baylor University
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in this problem. We're told that Airplane was flying from Chicago to San Fran and it took 3.75 hours, so that's gonna represent our time. Next, we're told that the cities are 1950 miles apart, so that's gonna represent our distance. We're being asked for the average speed. Well, to do this, we're going to use the formula D equals our times t, which is distance equals rate times time. Well, the average speed is what are our is referring to that's also known as the rate. So the fine are we simply need to substitute our time and distance into our formula. While we were told the distance was 1950 miles, we don't know the rates were gonna leave are there? But we know the time was 3.75 and now we simply need to solve this equation. Well, to do that, we just need to divide both sides of our equation by 3.75 because 3.7 fives will cancel each other up. Now, 1950 divided by 3.75 is 520. So that will be our rate. Now we just need to put in the units while the units for speed is distance over time. So our distance units is miles and our time units is ours. So what we found is the average feed would be 520 miles per hour.
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