00:01
We want a grammar that generates l.
00:05
So let's understand the pattern.
00:06
String's going to have b's anywhere.
00:07
The number of a's at the start must equal the number of a's at the end.
00:12
So we have epsilon b, b, a, b, a, b, a, b, a, b, a, b, a, b, a, b, a, b, a, b, a, a, a, a, a, so we can have bs in between freely, but a's must mirror at the start and the end...