Question
Set up a double integral and evaluate the surface integral $\iint_{S} g(x, y, z) d S$\iint_{S} \sqrt{x^{2}+y^{2}+z^{2}} d S, S \text { is the sphere } x^{2}+y^{2}+z^{2}=9
Step 1
The conversion is as follows: \[x = r\sin\phi\cos\theta\] \[y = r\sin\phi\sin\theta\] \[z = r\cos\phi\] where \(r = \sqrt{x^2 + y^2 + z^2}\) is the radial distance, \(\phi\) is the polar angle, and \(\theta\) is the azimuthal angle. Show more…
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Set up a double integral that equals $\iint_{S} g(x, y, z) d S$ and evaluate the surface integral $\iint_{S} g(x, y, z) d S .$ $\iint_{S} \sqrt{x^{2}+y^{2}+z^{2}} d S, S$ is the sphere $x^{2}+y^{2}+z^{2}=9$
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Set up a double integral that equals $\iint_{S} g(x, y, z) d S$ and evaluate the surface integral $\iint_{S} g(x, y, z) d S .$ $\iint z d S, S$ is the hemisphere $z=-\sqrt{9-x^{2}-y^{2}}$
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