set-up-an-integral-that-represents-the-length-of-the-curve-then-use-your-calculator-to-find-the-le-6

Question

Set up an integral that represents the length of the curve. Then use your calculator to find the length correct to four decimal places.

$ y^2  = \ln x $, $ -1 \le y \le 1 $

Harriet O&#x27;Brien · Accepted Answer

we have to find the length of the curve y squared equals Ln x on the interval. Why is greater than or equal to your negative one, but less under equal to one so we can rearrange why it&#x27;s where equals Alan X. By raising both sides to E. This will give us X equals e to the wise Square. Then we&#x27;ll want to find X prime to plug into our Ark formula equation. This is simply too. Why Times e two, the Y squared, plugging into our formula. Negative one for a and one for B one plus to Y E y squared squared again D y. If we plug this into our calculator, we should get around 4.2552

Problem

Find the exact length of the curve. $ y = 1 + …

Problem 8 Easy Difficulty

Set up an integral that represents the length of the curve. Then use your calculator to find the length correct to four decimal places.

$ y^2 = \ln x $, $ -1 \le y \le 1 $

Answer

$L \approx 4.2552$

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