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Problem

Find the exact length of the curve. $ y = 1 + …

02:02

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Problem 8 Easy Difficulty

Set up an integral that represents the length of the curve. Then use your calculator to find the length correct to four decimal places.

$ y^2 = \ln x $, $ -1 \le y \le 1 $


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Related Courses

Calculus 2 / BC

Calculus: Early Transcendentals

Chapter 8

Further Applications of Integration

Section 1

Arc Length

Related Topics

Applications of Integration

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Watch More Solved Questions in Chapter 8

Problem 1
Problem 2
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Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46

Video Transcript

we have to find the length of the curve y squared equals Ln x on the interval. Why is greater than or equal to your negative one, but less under equal to one so we can rearrange why it's where equals Alan X. By raising both sides to E. This will give us X equals e to the wise Square. Then we'll want to find X prime to plug into our Ark formula equation. This is simply too. Why Times e two, the Y squared, plugging into our formula. Negative one for a and one for B one plus to Y E y squared squared again D y. If we plug this into our calculator, we should get around 4.2552

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Related Topics

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