Question
Set up and evaluate the definite integral that gives the area of the region bounded by the graph of the function and the tangent line to the graph at the given point.$$y=\frac{2}{1+4 x^{2}}, \quad\left(\frac{1}{2}, 1\right)$$
Step 1
To do this, we differentiate $y$ with respect to $x$ to get the slope of the tangent line. The derivative of $y$ is given by: $$ y' = \frac{d}{dx} \left(\frac{2}{1+4x^2}\right) = -\frac{16x}{(1+4x^2)^2} $$ Substitute $x = \frac{1}{2}$ into the above equation to Show more…
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