00:01
So we have a sample of sales where n is 25, and we have no indication.
00:04
I'm assuming there would be many, many.
00:06
It doesn't say that the population size is, you know, say 50 companies and they're doing 25.
00:12
So i'm going to assume that there's a large, that n is large.
00:17
I'm also going to assume that these are approximately normally distributed.
00:22
And i'm also going to assume that these are simple random samples of different locations.
00:29
And so when i calculate the value here, and let me quick type in, we want a 90 % confidence interval in part a, a 90 % confidence interval for the mean.
00:49
And when i calculate the values, i get that the x bar here is 227 .5, excuse me, six.
00:59
And the sample standard deviation or the variability of those is 41 .86, and i'll call it 4.
01:07
Now, the t star value, we know our alpha value is 0 .1, therefore, the t value with 0 .05 in the upper tail, in the upper tail, in the upper tail, in the upper tail, in the upper tail, that is going to correspond with set 1 .1 .7, let me put the degrees of freedom first.
01:18
With the degrees of freedom of 24 and an upper tail of 0 .05, that is going to correspond with set one point, i'll put it this way, 1 .711.
01:34
So we would have our 227 .6 plus or minus that 1 .711 times the sample standard deviation of 41 .864 divided by the square root of 25 or 5.
01:51
And i believe those values come out to be 213 .28 to 241 .92.
02:03
So there is our confidence interval.
02:06
90 % confident.
02:07
Now part b asks us to find a width, actually two widths for a 95 % confidence interval for the mean and a 98 % confidence interval for the mean...