00:01
Okay, in this question, we are drawing resonant structures.
00:06
So let's get started.
00:08
Our first structure is n -o -3 -m minus.
00:16
And to draw the low -stnot structure, we calculate how many valence electrons we have.
00:21
So five from the nitrogen, six from each of the oxygens, and then one from the free electron from that negative charge.
00:30
And that is equal to 24.
00:36
And so if we draw out our lewis structure, let's say we have three bonds, two electrons per bond.
00:54
So we're going to subtract six electrons from our total.
00:57
That gives us 18 electrons to redistribute.
01:02
And that distributes nicely into six electrons per oxygen.
01:09
But if we look at this nice.
01:14
Nitrogen, this nitrogen only has access to six electrons.
01:20
Three bonds, two electrons each, no free pairs, that's six electrons.
01:24
Nitrogen's not happy.
01:26
So we're going to try moving two electrons from the oxygen as from free pairs into a bond.
01:38
So i'm going to volunteer these two electrons to form a bond.
01:44
And now it looks like we're in good shape because this nitrogen has four bonds.
01:48
Eight electrons, and this oxygen still has eight electrons, four free electrons, and then four from lebovans.
01:57
So this is a possible structure.
02:01
Now with resonant structures, we can reach the same distribution of electrons more or less, but with different oxygen atoms.
02:17
So in this case, the nitrogen is double bonded to the oxygen on the right hand side.
02:29
And there's not a big difference between these two in terms of stability because, well, if you calculate your formal charges, they're all going to be the same.
02:41
Likewise, we can draw one more configuration where the double bond is on the left hand oxygen.
02:58
And all of these structures have the same energetic favorability.
03:05
So you would expect a 33 % distribution for each of these individual resonant structures.
03:18
Okay.
03:20
Our next compound is nitric acid.
03:24
So we have h .n .o .3.
03:35
Okay, from the previous question, you know that the structure for the no3 is going to look something like this.
03:48
And with this h, we are going to just add a hydrogen to one of these oxygens.
04:00
And we are not going to forget to dot in our free electrons.
04:12
Okay.
04:13
So that is a possible little structure for this nitric acid.
04:18
And let's just do a quick sanity check to make sure we have all the right electrons.
04:24
So we know hydrogen has one electron, nitrogen brings five, and the three oxygens bring a total of 18.
04:32
So in total we would expect 24 electrons.
04:40
We have eight here.
04:41
We have eight here, and we have eight here.
04:47
Eight times three is 24.
04:49
Looks good.
04:51
And all of the atoms are satisfied the octet rule with the exception of hydrogen...