00:01
Well, instantaneous displacement can be written as x is equal to a times sine omega -t.
00:11
Now let's differentiate this function with respect to time.
00:16
So taking d divided by d t on both sides.
00:24
So amplitude is a constant quantity.
00:27
Therefore, we have a derivative of sine function.
00:37
And dx divided by d t equals a times omega times cosine of omega t.
00:46
Now let's differentiate again d square x divided by d t square.
00:53
So differentiating again we get a minus a times omega square times sine into omega t.
01:04
Well, the equation 13 .3 is m times d square x divided by d t square is equal to minus kx, which is the differential form of newton's second law...