00:03
Let's try synthesizing the following compounds from alkenes.
00:08
Well, if we take this first one and we know we're adding this part because that's an easy substituent to add.
00:20
So if we look at that, well, we can say that our alken was this molecule, propene.
00:29
And what we added was this substituent, which would be methanol.
00:40
Under catalytic h2s -o -4.
00:45
And we can do that to produce this ether.
00:54
For the next one, well, we're adding two bromines.
00:58
So right off the bat, we can just remove them and say that the carbons between them have a double bond, and we're adding br2.
01:14
For this one, well, we can say that we're adding this alcohol group.
01:20
So if we remove that and put a double bond, with the carbons involved.
01:26
There's only one carbon bonded close to that alcohol, so we will have to use this alken.
01:33
And if we want to produce this alcohol, we're going to have to use anti -marcovnikov addition, because we want it on this carbon, which would mean we add borohyd, thf, and we use h202, h2o, and so, some type of base.
02:02
For this one, we can remove our added group, which is usually going to be the fancy group.
02:09
We're looking at alcohols, ethers, halogens, anything with an oxygen or a halogen is kind of a safe bet with these problems.
02:22
If you're trying to synthesize molecules using alkenes, what you're looking for is something that'll add oxygen.
02:31
Something that'll add halogens.
02:34
So if we just remove that entirely, what we end up getting is we can have one of two alkenes.
02:41
We can have this alkenes or we can have this alken.
02:47
Now, i'm going to use this alken because it's a more stable and more commercially available alken than this one...