00:01
Okay, so we're going to create the following compounds from ethline, which is a two carbon alkyn.
00:08
And the first one we want to create is one pentine three all.
00:14
So pent is five.
00:16
And the one impository an alcon on carbon one.
00:19
The three all is an alcohol on carbon three.
00:22
And if we redraw the carbon with the alcohol, we would have started the ketone.
00:27
On the right, we have an ethyl.
00:29
And it would have been a hydrogen here.
00:32
So if we react to ethine with sodium amide, will have a radical reaction and it'll lose the hydrogen.
00:40
We'll get a blue pair of electrons on this carbon making a nucleophilic.
00:47
So reacting with the ketone.
00:51
It's going to attack the carbonyl carbon and reacting with water as well will give us the alcohol.
01:10
There's the product.
01:12
So for b, we want to create one phenol, two butin, one all.
01:23
So butin is butene.
01:25
And the one phenol and the one all implies you can alcohol on an alcohol and a phenol in carbon one and the two, the alkyne is on carbon two.
01:35
So drawing the phenyl first, which is a benzeneering derivative...