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Show that 1 cal/g ? $^{\circ} \mathrm{C}=1$ kcal/kg ?$^{\circ} \mathrm{C}$

$\frac{1 c a l}{g .^{0} C}=\frac{10^{3} c a l}{10^{3} g .^{0} C}=\frac{K c a l}{K g .^{0} C}$

Physics 101 Mechanics

Chapter 14

Heat and Heat Transfer Methods

Thermal Properties of Matter

Cornell University

University of Michigan - Ann Arbor

University of Sheffield

McMaster University

Lectures

02:20

A solid, liquid, or gas is one of the three main states of matter. Solids have a definite shape and volume, and retain their shape when a force is applied to them. They are rigid, and do not flow to take on the shape of a container, but retain their own shape. Solids are held together by intermolecular forces, which are usually chemical bonds. Liquids have a free-flowing, continuous surface, and take the shape of a container. They flow to fill an available space. Their particles do not have a definite shape or volume, and they are not rigid. Gases have no definite shape or volume. They are not held together, and are not rigid. They flow to fill an available space. Gases are often described as being the state of matter with the lowest density.

06:13

Matter is a state of aggregation for a collection of atoms, molecules, ions, or particles. It is a general term for the substance of which all physical objects consist.

05:45

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03:27

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02:17

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04:25

02:06

05:09

Okay. This question is asking us to prove that one calorie per gram times degrees Celsius is the same as one. Kill a cow per kilogram times degrees Celsius. So this is easy because we could multiply anything by one so one calorie over grams times degree Celsius. Multiply this by 1000 over 1000 because that equals one and then we can just rewrite because 1000 calories is the same as one killer calorie. That's the definition of Kilo is 1000. Same thing goes for grams. That's one kilogram and then degree Celsius stays the same, so there.

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