Show that
$$
2\left(k \cdot p^{\prime}\right)\left(k^{\prime} \cdot p\right)=\left(p-k^{\prime}\right)^{2}\left(k^{\prime} \cdot p\right)=\left(m^{2}-2 m \omega^{\prime}\right) m \omega^{\prime}
$$
in the muon rest frame, where $p=(m, 0,0,0)$.
Gathering these results together, the decay rate in the muon rest frame is
$$
\begin{aligned}
d \Gamma=& \frac{G^{2}}{2 m \pi^{5}} \frac{d^{3} p^{\prime}}{2 E^{\prime}} \frac{d^{3} k^{\prime}}{2 \omega^{\prime}} m \omega^{\prime}\left(m^{2}-2 m \omega^{\prime}\right) \\
& \times \delta\left(m^{2}-2 m E^{\prime}-2 m \omega^{\prime}+2 E^{\prime} \omega^{\prime}(1-\cos \theta)\right)
\end{aligned}
$$
and, as for $\beta$-decay, we can replace $d^{3} p^{\prime} d^{3} k^{\prime}$ by
$$
4 \pi E^{\prime 2} d E^{\prime} 2 \pi \omega^{\prime 2} d \omega^{\prime} d \cos \theta
$$