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Show that at the inflection point of $(4) p=1 / 2$. Hint: differentiate \frac{d p}{d t}=k p(1-p).

Algebra

Chapter 4

Exponential and Logarithmic Functions

Section 7

Applications of Exponential and Logarithmic Functions

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Lectures

02:39

Show that the function $f(…

03:36

Find the point(s) of infle…

0:00

Show that the inflection p…

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02:48

Show that if you different…

in the equation here we're recording that The function F x has the inflection pond Yeah, and X equal to see if we have the AP double Prime Member C equal to zero and, uh, at the sea the F double prime X we gender sign here. So in this question, here were given the function F x echoed you Nah, each the minus X square on with you. Now we need to find a second the review platform. We need to find the first day review first. Then we get equal to Eva minus x square with you. But the general, we need two times a minus X here in front and then the second derivative here. We need to blind the broader group here U and V. So we have the minus age of the minus x squared off with you. I don't have this One will be in, uh, plus nah X square age. The minus x square are with you. So we sent us on equal to zero and then we see we confront that the age of the minus X squared over two outside and some have the X squared minus one equal to zero is an equal to zero n implies that the X squared minus one must equal to zero. Because, exponential, we never equal to zero. And if it means that the X will echo to bless a minus one. So we see this one will be the isn't obliged. And the F number prime on the plus and minus one, it will be coaches. Oh, and also on the aftermath. Bram here within the 11, the right sign the blessed minus one which undersigned definition implies that Ah, also we have here the F number prime under blossom minus one, and from the x Gent sign at plus minus one. Therefore, from here we can conclude that the function F X has the inflection point. Yeah, at X in culture blossom minus one. Yes. Yeah.

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