00:01
For number 53, recall that if r is less than or equal to 0, point p can be expressed as r, theta plus pi.
00:19
And it would follow that pf equals r, and the pd equals k minus r, cosine, so we can work with the equality, pf, e, times pd, r making substitutions, r equals e times k minus r, cosine theta.
00:55
Solving for r yields k, i'm sorry, equals r equals k -e over 1 plus e, cosine.
01:11
Similarly, recall that expressing p as point r -theta can be expressed as negative r, theta minus pi.
01:31
In which case pd equals negative r and pf takes the form negative r cosine theta minus pi minus k...