00:01
In this question we have to show that for an ideal gas the pressure is given by one -third of the mass density times the r -emass velocity squared.
00:11
So how can we show that? i will begin by using this equation.
00:16
So the ideal gas law.
00:17
The ideal gas law tells us that the pressure times the volume is equal to the number of molecules or atoms times boltzman's constant times the temperature.
00:28
Then we can solve this equation.
00:30
For the pressure to get that the pressure is given by n times k times t divided by the volume.
00:38
Now take a look at this factor of k times t right here.
00:43
So this factor of k times t also appear in the expression for the average kinetic energy of a single molecule or atom of ideal gas.
00:53
So we can actually serve this equation for k times t.
00:58
By doing that, you get the following.
01:01
So the average kinetic energy is 3 divided by 2 times k times t.
01:08
It means that k times t is equal to 2 divided by 3 times the average kinetic energy.
01:17
Then, plugging in this result into this equation results in the following.
01:22
The pressure is given by n divided by v times 2, divided by 3 times the average kinetic energy.
01:34
Now, we must remember from classical mechanics that the kinetic energy is the mass times the velocity squared divided by 2...