Question
Show that, for any integer $n$,$$\frac{1}{2 n} 2^{2 n} \leq\binom{ 2 n}{n} \leq 2^{2 n} .$$
Step 1
Step 1: We start with the binomial coefficient \(\binom{2n}{n}\), which is defined as: \[ \binom{2n}{n} = \frac{(2n)!}{(n!)^2} \] Show more…
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