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Show that for any relative velocity $v$ between two observers, a beam of light projected by one directly away from the other will move away at the speed of light (provided that $v$ is less than $c,$ of course).

Hence it is proved that the light beam will also move away from the secondobserver with speed $c .$

Physics 103

Chapter 28

Special Relativity

Relativity

University of Michigan - Ann Arbor

Simon Fraser University

University of Winnipeg

Lectures

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Use relativistic velocity …

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Is the relativistic rule

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Light travels from point $…

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Astronomy. When two galaxi…

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CE Two observers are movin…

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Same two observers as in t…

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Show that when light refle…

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A light beam is emitted at…

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Well, in this case, the relative velocity between the observer is a V eyes the relative velocity between the observer and the relative velocity off the signal with respect to the first observer is ah you prime. And it's equal to minus c. So the relative velocity you off. The signal with respect to the second observer is given by you is equal to replace you. Prime divided by one place Oh, the you prime divided by C square And this becomes we minus c divided by one minus We see divided by C square on dhe. Further simplifying, we get a minus c into we mind you see, divided by we minus c and this gives us U equals minus C. Hence, it is proof that the light being will also move away from the second Observer. Make speed. Uh, see

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